Weibull distribution (EN)

ATTENTION - instead of a decimal comma should be used decimal DOT ! (EN)

**सूत्र**
$P(x)=\\ & \begin{cases} \frac{k}{\lambda}\left(\frac{x}{\lambda}\right)^{k-1}e^{-(x/\lambda)^{k}} & x\geq0 ,\\0 & x<0 ,\end{cases}$
$E(X)=\lambda \Gamma\left(1+\frac{1}{k}\right)$
$D(X)=\lambda^2\left[\Gamma\left(1+\frac{2}{k}\right) - \left(\Gamma\left(1+\frac{1}{k}\right)\right)^2\right]$
$\frac{\Gamma\left(1+\frac{3}{k}\right)\lambda^3-3\mu\sigma^2-\mu^3}{\sigma^3}$
$\gamma _{2}=\frac{-6\Gamma_1^4+12\Gamma_1^2\Gamma_2-3\Gamma_2^2-4\Gamma_1\Gamma_3+\Gamma_4}{[\Gamma_2-\Gamma_1^2]^2}$